Total Energy At Low Speeds Relating to Mass Energy Equivalence Must Include Linear, Rotational and Vibrational Kinetic Energies

Einstein calculated the total energy at low speeds to be $E_{total}= m_0c^2 + 1/2m_0v^2$. However, the total energy at low speeds must also include the rotational and vibrational kinetic energies as well.Therefore, the mathematical relationship must include these factors. If $1/2I\omega^2$ is the rotational kinetic energy of the mass, and $1/2kx_0^2$ is the vibrational kinetic energy of the mass, the total energy of the mass must be $E_{total}= m_0c^2 + 1/2mv^2 + 1/2I\omega^2 +1/2kx_0^2$.