Calculation of the radius of the universe

Scientists speculate that the mass of the universe is 10⁵⁶ grams. The density of the universe is 10⁹⁴g/cm after 10^-43 seconds after the Big Bang. At that moment, the volume of the universe is 10⁵⁶/10⁹⁴=10^-38, and the radius of the universe is 10^-38, which is equal to three times. 2.15×10^-13cm. The universe expands in rotation, the total mass of the universe is constant, and the angular momentum is conserved. M1V1R1=M2V2R2, where M1, V1, and R1 represent the mass, rotation speed, and radius of the super-explosion 10^-43 seconds, respectively. V2 and R2 represent the mass, rotation speed and radius of the universe, respectively. Since M1=M2, the law of conservation of angular momentum of the universe can be simplified as: V1R1=V2R2, V1/V2=R2/R1=4.65×10⁴¹, at this time R1=2.15×10^-13, R2 is the current universe radius: R2 = 4.65 × 10⁴¹ × 2.15 × 10^-13 = 10²⁹cm = 10²⁷m, which is the radius of the current universe. What is the value and how many light years? A light year is about 9.5×10¹⁵m, 10²⁷/9.5×10¹⁵=1.05×10¹¹ light years, and 105 billion light years.