Energy conservation analysis of changes in photon velocity

The energy of a photon is mc^2. Any two adjacent photons are entangled, and entanglement must have potential energy. The energy of photons in vacuum is the sum of kinetic energy and elasticity, mc^2= mc^2/2+ kΔλ^2/2——(1), The equation for photons entering other media from vacuum is: mc^2=mv^2/2+kΔλ^2/2——(2), Among them, k is the dielectric constant, equivalent to the stiffness coefficient of a spring, and Δ λ is the change in wavelength. According to mc^2=mv^2/2+k Δ λ ^2/2- (2), it is calculated that: v^2= c^2- kΔλ^2/m, Obviously, if v<c, the speed of photons must be less than the speed of light. Analyze the equation mc^2=mv^2/2+k Δ λ ^2/2- (2), where the wavelength of a photon in an absolute vacuum state is Δ λ=0, i.e. mc^2=mv^2/2, and v is equal to twice the speed of light with the root sign. So we come to the conclusion that the existing vacuum is not an absolute vacuum, photons have an absolute vacuum velocity equal to twice the speed of light at the root, and photons can exceed the speed of light in special spaces.