Calculation of absolute Hubble constant and radius of the universe

On the cosmic scale, the retrograde velocity of a galaxy is a curved motion with a maximum radius. The absolute Hubble law can be written as: v=H0 x x, where v is the absolute linear velocity of the galaxy, x is the distance from the center of the universe, and H0 is the absolute Hubble constant. Explanation: The center of the universe can be understood as the starting position of the universe. The gravitational law I discovered within the universe: F=G ρ 4 π xm/3, where m is the mass of the galaxy, x is the distance between the galaxy and the center of the universe, and G is the gravitational constant ρ It is the density of the universe. According to the relationship between curved motion and gravity, it can be concluded that F=G ρ 4 π xm/3=v ^ 2m/x, using the absolute Hubble law v=H0 x x, substitute the velocity v into F=G ρ 4 π xm/3=v ^ 2m/x, and simplified to H0 ^ 2=G ρ 4 π/3, the cosmic density must not exceed 2.1 x 10 ^ -28 kg/m ^ 3, and the absolute value of the Hubble constant is "G" ρ The square root of 4 π/3 "is equal to 2.4 x 10 ^ -19. The final radius of the universe is R=c/H0=3 x 10 ^ 8/2.4 x 10 ^ -19=1.25 x 10 ^ 27m, where c is the speed of light.