Charge, from EM fields only.

Purely electromagnetic particle (PEP) models of an electron have until now failed because they do not account for ''charge''. A model of the electron, built from EM fields only, has been found that generates a \textbf {vxB} inverse square field that resembles the electric field \textbf {E} we associate with charge. Does this model contain charge? Not really. Gauss' law says yes, but div \textbf {vxB} finds no charge density. ``Charge'' is a mathematical fiction, useful but not fundamental. This model begins with a magnetic flux quantum configured as a magnetic dipole, $\mu$, spinning at $\sqrt{3}$ times the Compton frequency $ \nu_C = mc^2 /h$. As it decays, energy is transferred to a toroidal displacement current. Oscillation between these configurations proceeds at $\nu_C$. The EM assembly carries angular momentum \textbf {L}, spinning about $\mu$. Spinning \textbf {B} leads to \textbf {vxB}, an electric field that arises everywhere in space from spinning \textbf {B} and not from some compact central ``charge''. Elastic Coulomb scattering must find the electron to be a point particle, without size even though the EM structure itself is huge. $\mu$ undulates but does not reverse polarity. Faraday's static \textbf {E} field does not exist in nature. The electric field about an electron is \textbf {vxB}, inverse square and undulating at $1.24x10^{20} $ Hz.